Helix
'S' et helix 'Z' or 'left' helix and
'right' helix .
Just a short revision of notions exposed in Bat's Belfry_4 about
sign
of crossings but this time applied to helices.
Procedure
to be followed .
Please make note that result will be correct even if you
put the vertical
orientation
upside-down. It will still gives the
correct answer.
A tip : make use of the
angle between the two arrow symbols signs
showing
the directions..
Signing
of crossing and 'Z' / 'S' are sure tools
, even if you put upside-down the vertical
orientation
results
will
not change.
That make derelict the use, to define
orientation, of ways full of confusion potential such a :
with/against the sun , (inverse), corkscrew, (anti) clockwise,
(in) direct, left/right...
I hold the opinion that it
is
not quite
precise to say, that
the strands *are* helices and
to
speak about cordage as 'parallel helices
cordages', or to
stated
that these cordages are not
laid or twisted but spun cordage.
Strands follow an approximatively helicidal course but are not
really helices except in
modelization.
By the way, while we are there, just as I do not think
pedantic to take care not to confuse
'ball' (volume) with 'sphere' (area), I do not think it is pedantic to
avoid to confuse
'spiral' (a curve on a plane) with 'helix' (a curve in 3 D) .
It is simply
observing a 'guarded' or 'surveyed'
language as must be
the case when speaking
about technical topics.
Putting apart the straight line parallel to the axis
(génératrice in French ) which is the course
asking for
the greater energy coming up, the most economical route to go along a
cylinder
is the helix. The slope is easier and after one full revolution you
arrive
directly above your
point of departure.
Squirrels know that and follow such
courses.
Fibres, threads, strands will also take
the shortest way same under an axial torque
:
It
is easy to convince yourself :
Flatten
a cylinder , decide about the vertical distance to run upward or
downward.
Trace a straight line from the chosen corner to the one directly
opposite -diagonally -.
Make again the rectangle into a cylinder.
Helix is there.
For a cylinder of given height the distance for one full revolution of
the helix
is directly dependent of the cylinder diameter.
The
greater the diameter the greater the distance.
It follows that for a given length of material before any laying or
twisting, there will be after
twisting a greater force applied where
the
diameter is greater.
What is 'gained' in length is paid for by a diminution of the section
(diameter) of the fibres
and by a greater tension existing in them.
Note : the
cordage as a whole is shortened.
Pulling tension is some times so high that breakage happen while
laying/twisting, the more
so if it is 'hard lay' : this is "loss to the
lay"
It must be realized that from the centre to the periphery
:
--- either you will have to allow for more matter before commencing, so
that
after the
twisting motion has been applied all the fibres are under an
equal tension whatever be
their position.